-8x2+19x=-80

Solution for -8x2+19x=-80 equation:

-8x^2+19x=-80

We move all terms to the left:

-8x^2+19x-(-80)=0

We add all the numbers together, and all the variables

-8x^2+19x+80=0

a = -8; b = 19; c = +80;
Δ = b2-4ac
Δ = 192-4·(-8)·80
Δ = 2921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{2921}}{2*-8}=\frac{-19-\sqrt{2921}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{2921}}{2*-8}=\frac{-19+\sqrt{2921}}{-16}
$