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-8x^2+41x-1=0
a = -8; b = 41; c = -1;
Δ = b2-4ac
Δ = 412-4·(-8)·(-1)
Δ = 1649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-\sqrt{1649}}{2*-8}=\frac{-41-\sqrt{1649}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+\sqrt{1649}}{2*-8}=\frac{-41+\sqrt{1649}}{-16} $
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