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-8x^2-19x+9=0
a = -8; b = -19; c = +9;
Δ = b2-4ac
Δ = -192-4·(-8)·9
Δ = 649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{649}}{2*-8}=\frac{19-\sqrt{649}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{649}}{2*-8}=\frac{19+\sqrt{649}}{-16} $
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