-8y+2(y-4)=-38

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Solution for -8y+2(y-4)=-38 equation: 



-8y+2(y-4)=-38

We move all terms to the left:

-8y+2(y-4)-(-38)=0

We add all the numbers together, and all the variables

-8y+2(y-4)+38=0

We multiply parentheses

-8y+2y-8+38=0

We add all the numbers together, and all the variables

-6y+30=0

We move all terms containing y to the left, all other terms to the right

-6y=-30

y=-30/-6

y=+5

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