-8y+22=-6y(y-2)

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Solution for -8y+22=-6y(y-2) equation:



-8y+22=-6y(y-2)
We move all terms to the left:
-8y+22-(-6y(y-2))=0
We calculate terms in parentheses: -(-6y(y-2)), so:
-6y(y-2)
We multiply parentheses
-6y^2+12y
Back to the equation:
-(-6y^2+12y)
We get rid of parentheses
6y^2-12y-8y+22=0
We add all the numbers together, and all the variables
6y^2-20y+22=0
a = 6; b = -20; c = +22;
Δ = b2-4ac
Δ = -202-4·6·22
Δ = -128
Delta is less than zero, so there is no solution for the equation

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