-8y+3(y-4)=-7

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Solution for -8y+3(y-4)=-7 equation: 



-8y+3(y-4)=-7

We move all terms to the left:

-8y+3(y-4)-(-7)=0

We add all the numbers together, and all the variables

-8y+3(y-4)+7=0

We multiply parentheses

-8y+3y-12+7=0

We add all the numbers together, and all the variables

-5y-5=0

We move all terms containing y to the left, all other terms to the right

-5y=5

y=5/-5

y=-1

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