-8y+4(y-4)=-32

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Solution for -8y+4(y-4)=-32 equation: 



-8y+4(y-4)=-32

We move all terms to the left:

-8y+4(y-4)-(-32)=0

We add all the numbers together, and all the variables

-8y+4(y-4)+32=0

We multiply parentheses

-8y+4y-16+32=0

We add all the numbers together, and all the variables

-4y+16=0

We move all terms containing y to the left, all other terms to the right

-4y=-16

y=-16/-4

y=+4

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