-8y+6(y+3)=2

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Solution for -8y+6(y+3)=2 equation:



-8y+6(y+3)=2
We move all terms to the left:
-8y+6(y+3)-(2)=0
We multiply parentheses
-8y+6y+18-2=0
We add all the numbers together, and all the variables
-2y+16=0
We move all terms containing y to the left, all other terms to the right
-2y=-16
y=-16/-2
y=+8

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