-8y+6(y+3)=2

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Solution for -8y+6(y+3)=2 equation: 



-8y+6(y+3)=2

We move all terms to the left:

-8y+6(y+3)-(2)=0

We multiply parentheses

-8y+6y+18-2=0

We add all the numbers together, and all the variables

-2y+16=0

We move all terms containing y to the left, all other terms to the right

-2y=-16

y=-16/-2

y=+8

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