-8y-129=-3y+-9(-5+7y)

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Solution for -8y-129=-3y+-9(-5+7y) equation: 



-8y-129=-3y+-9(-5+7y)

We move all terms to the left:

-8y-129-(-3y+-9(-5+7y))=0

We add all the numbers together, and all the variables

-8y-(-3y+-9(7y-5))-129=0

We use the square of the difference formula

-8y-(-3y-9(7y-5))-129=0



We calculate terms in parentheses: -(-3y-9(7y-5)), so:

-3y-9(7y-5)

We multiply parentheses

-3y-63y+45

We add all the numbers together, and all the variables

-66y+45

Back to the equation:

-(-66y+45)



We get rid of parentheses

-8y+66y-45-129=0

We add all the numbers together, and all the variables

58y-174=0

We move all terms containing y to the left, all other terms to the right

58y=174

y=174/58

y=3

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