-8z+28=-2(z-14)-6z

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Solution for -8z+28=-2(z-14)-6z equation: 



-8z+28=-2(z-14)-6z

We move all terms to the left:

-8z+28-(-2(z-14)-6z)=0



We calculate terms in parentheses: -(-2(z-14)-6z), so:

-2(z-14)-6z

We add all the numbers together, and all the variables

-6z-2(z-14)

We multiply parentheses

-6z-2z+28

We add all the numbers together, and all the variables

-8z+28

Back to the equation:

-(-8z+28)



We get rid of parentheses

-8z+8z-28+28=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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