-9(-3x+5)+x+192=2(-x-4)-9x-40

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Solution for -9(-3x+5)+x+192=2(-x-4)-9x-40 equation: 



-9(-3x+5)+x+192=2(-x-4)-9x-40

We move all terms to the left:

-9(-3x+5)+x+192-(2(-x-4)-9x-40)=0

We add all the numbers together, and all the variables

-9(-3x+5)+x-(2(-1x-4)-9x-40)+192=0

We add all the numbers together, and all the variables

x-9(-3x+5)-(2(-1x-4)-9x-40)+192=0

We multiply parentheses

x+27x-(2(-1x-4)-9x-40)-45+192=0



We calculate terms in parentheses: -(2(-1x-4)-9x-40), so:

2(-1x-4)-9x-40

We add all the numbers together, and all the variables

-9x+2(-1x-4)-40

We multiply parentheses

-9x-2x-8-40

We add all the numbers together, and all the variables

-11x-48

Back to the equation:

-(-11x-48)



We add all the numbers together, and all the variables

28x-(-11x-48)+147=0

We get rid of parentheses

28x+11x+48+147=0

We add all the numbers together, and all the variables

39x+195=0

We move all terms containing x to the left, all other terms to the right

39x=-195

x=-195/39

x=-5

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