-9(-5b-3)+16b=5(12b+20)

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Solution for -9(-5b-3)+16b=5(12b+20) equation: 



-9(-5b-3)+16b=5(12b+20)

We move all terms to the left:

-9(-5b-3)+16b-(5(12b+20))=0

We add all the numbers together, and all the variables

16b-9(-5b-3)-(5(12b+20))=0

We multiply parentheses

16b+45b-(5(12b+20))+27=0



We calculate terms in parentheses: -(5(12b+20)), so:

5(12b+20)

We multiply parentheses

60b+100

Back to the equation:

-(60b+100)



We add all the numbers together, and all the variables

61b-(60b+100)+27=0

We get rid of parentheses

61b-60b-100+27=0

We add all the numbers together, and all the variables

b-73=0

We move all terms containing b to the left, all other terms to the right

b=73

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