-9(-x-1)+3(-x+2)=10(x-2)+17

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Solution for -9(-x-1)+3(-x+2)=10(x-2)+17 equation: 



-9(-x-1)+3(-x+2)=10(x-2)+17

We move all terms to the left:

-9(-x-1)+3(-x+2)-(10(x-2)+17)=0

We add all the numbers together, and all the variables

-9(-1x-1)+3(-1x+2)-(10(x-2)+17)=0

We multiply parentheses

9x-3x-(10(x-2)+17)+9+6=0



We calculate terms in parentheses: -(10(x-2)+17), so:

10(x-2)+17

We multiply parentheses

10x-20+17

We add all the numbers together, and all the variables

10x-3

Back to the equation:

-(10x-3)



We add all the numbers together, and all the variables

6x-(10x-3)+15=0

We get rid of parentheses

6x-10x+3+15=0

We add all the numbers together, and all the variables

-4x+18=0

We move all terms containing x to the left, all other terms to the right

-4x=-18

x=-18/-4

x=4+1/2

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