-9(1+3z)=-22

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Solution for -9(1+3z)=-22 equation: 



-9(1+3z)=-22

We move all terms to the left:

-9(1+3z)-(-22)=0

We add all the numbers together, and all the variables

-9(3z+1)-(-22)=0

We add all the numbers together, and all the variables

-9(3z+1)+22=0

We multiply parentheses

-27z-9+22=0

We add all the numbers together, and all the variables

-27z+13=0

We move all terms containing z to the left, all other terms to the right

-27z=-13

z=-13/-27

z=13/27

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