-9(1-x)+15-28=35(1-x)-7

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Solution for -9(1-x)+15-28=35(1-x)-7 equation: 



-9(1-x)+15-28=35(1-x)-7

We move all terms to the left:

-9(1-x)+15-28-(35(1-x)-7)=0

We add all the numbers together, and all the variables

-9(-1x+1)-(35(-1x+1)-7)+15-28=0

We add all the numbers together, and all the variables

-9(-1x+1)-(35(-1x+1)-7)-13=0

We multiply parentheses

9x-(35(-1x+1)-7)-9-13=0



We calculate terms in parentheses: -(35(-1x+1)-7), so:

35(-1x+1)-7

We multiply parentheses

-35x+35-7

We add all the numbers together, and all the variables

-35x+28

Back to the equation:

-(-35x+28)



We add all the numbers together, and all the variables

9x-(-35x+28)-22=0

We get rid of parentheses

9x+35x-28-22=0

We add all the numbers together, and all the variables

44x-50=0

We move all terms containing x to the left, all other terms to the right

44x=50

x=50/44

x=1+3/22

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