-9(2b+2)+(19b-5)=0

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Solution for -9(2b+2)+(19b-5)=0 equation:


Simplifying
-9(2b + 2) + (19b + -5) = 0

Reorder the terms:
-9(2 + 2b) + (19b + -5) = 0
(2 * -9 + 2b * -9) + (19b + -5) = 0
(-18 + -18b) + (19b + -5) = 0

Reorder the terms:
-18 + -18b + (-5 + 19b) = 0

Remove parenthesis around (-5 + 19b)
-18 + -18b + -5 + 19b = 0

Reorder the terms:
-18 + -5 + -18b + 19b = 0

Combine like terms: -18 + -5 = -23
-23 + -18b + 19b = 0

Combine like terms: -18b + 19b = 1b
-23 + 1b = 0

Solving
-23 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '23' to each side of the equation.
-23 + 23 + 1b = 0 + 23

Combine like terms: -23 + 23 = 0
0 + 1b = 0 + 23
1b = 0 + 23

Combine like terms: 0 + 23 = 23
1b = 23

Divide each side by '1'.
b = 23

Simplifying
b = 23

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