-9(2b+3)+(19b-4)=0

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Solution for -9(2b+3)+(19b-4)=0 equation:


Simplifying
-9(2b + 3) + (19b + -4) = 0

Reorder the terms:
-9(3 + 2b) + (19b + -4) = 0
(3 * -9 + 2b * -9) + (19b + -4) = 0
(-27 + -18b) + (19b + -4) = 0

Reorder the terms:
-27 + -18b + (-4 + 19b) = 0

Remove parenthesis around (-4 + 19b)
-27 + -18b + -4 + 19b = 0

Reorder the terms:
-27 + -4 + -18b + 19b = 0

Combine like terms: -27 + -4 = -31
-31 + -18b + 19b = 0

Combine like terms: -18b + 19b = 1b
-31 + 1b = 0

Solving
-31 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '31' to each side of the equation.
-31 + 31 + 1b = 0 + 31

Combine like terms: -31 + 31 = 0
0 + 1b = 0 + 31
1b = 0 + 31

Combine like terms: 0 + 31 = 31
1b = 31

Divide each side by '1'.
b = 31

Simplifying
b = 31

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