-9(3b+1)+(28-3)=0

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Solution for -9(3b+1)+(28-3)=0 equation:


Simplifying
-9(3b + 1) + (28 + -3) = 0

Reorder the terms:
-9(1 + 3b) + (28 + -3) = 0
(1 * -9 + 3b * -9) + (28 + -3) = 0
(-9 + -27b) + (28 + -3) = 0

Combine like terms: 28 + -3 = 25
-9 + -27b + (25) = 0
-9 + -27b + 25 = 0

Reorder the terms:
-9 + 25 + -27b = 0

Combine like terms: -9 + 25 = 16
16 + -27b = 0

Solving
16 + -27b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -27b = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -27b = 0 + -16
-27b = 0 + -16

Combine like terms: 0 + -16 = -16
-27b = -16

Divide each side by '-27'.
b = 0.5925925926

Simplifying
b = 0.5925925926

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