-9(3b+1)+(28b-3)=0

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Solution for -9(3b+1)+(28b-3)=0 equation:


Simplifying
-9(3b + 1) + (28b + -3) = 0

Reorder the terms:
-9(1 + 3b) + (28b + -3) = 0
(1 * -9 + 3b * -9) + (28b + -3) = 0
(-9 + -27b) + (28b + -3) = 0

Reorder the terms:
-9 + -27b + (-3 + 28b) = 0

Remove parenthesis around (-3 + 28b)
-9 + -27b + -3 + 28b = 0

Reorder the terms:
-9 + -3 + -27b + 28b = 0

Combine like terms: -9 + -3 = -12
-12 + -27b + 28b = 0

Combine like terms: -27b + 28b = 1b
-12 + 1b = 0

Solving
-12 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 1b = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 1b = 0 + 12
1b = 0 + 12

Combine like terms: 0 + 12 = 12
1b = 12

Divide each side by '1'.
b = 12

Simplifying
b = 12

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