-9(3b+1)+(28b-6)=0

Solution for -9(3b+1)+(28b-6)=0 equation:

Simplifying
-9(3b + 1) + (28b + -6) = 0

Reorder the terms:
-9(1 + 3b) + (28b + -6) = 0
(1 * -9 + 3b * -9) + (28b + -6) = 0
(-9 + -27b) + (28b + -6) = 0

Reorder the terms:
-9 + -27b + (-6 + 28b) = 0

Remove parenthesis around (-6 + 28b)
-9 + -27b + -6 + 28b = 0

Reorder the terms:
-9 + -6 + -27b + 28b = 0

Combine like terms: -9 + -6 = -15
-15 + -27b + 28b = 0

Combine like terms: -27b + 28b = 1b
-15 + 1b = 0

Solving
-15 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + 1b = 0 + 15

Combine like terms: -15 + 15 = 0
0 + 1b = 0 + 15
1b = 0 + 15

Combine like terms: 0 + 15 = 15
1b = 15

Divide each side by '1'.
b = 15

Simplifying
b = 15