-9(3b+1)+(28b-8)=0

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Solution for -9(3b+1)+(28b-8)=0 equation:


-9(3b+1)+(28b-8)=0

We simplify the equation to the form, which is simple to understand 
-9(3b+1)+(28b-8)=0

Reorder the terms in parentheses
+(-27b-9)+(28b-8)=0

Remove unnecessary parentheses
-27b-9+(+28b-8+)=0

Remove unnecessary parentheses
-27b-9+28b-8=0

We move all terms containing b to the left and all other terms to the right. 
-27b+28b=0+9+8

We simplify left and right side of the equation. 
+1b=+17

We divide both sides of the equation by 1 to get b. 
b=17

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