-9(3b+2)+(28b-5)=0

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Solution for -9(3b+2)+(28b-5)=0 equation:


Simplifying
-9(3b + 2) + (28b + -5) = 0

Reorder the terms:
-9(2 + 3b) + (28b + -5) = 0
(2 * -9 + 3b * -9) + (28b + -5) = 0
(-18 + -27b) + (28b + -5) = 0

Reorder the terms:
-18 + -27b + (-5 + 28b) = 0

Remove parenthesis around (-5 + 28b)
-18 + -27b + -5 + 28b = 0

Reorder the terms:
-18 + -5 + -27b + 28b = 0

Combine like terms: -18 + -5 = -23
-23 + -27b + 28b = 0

Combine like terms: -27b + 28b = 1b
-23 + 1b = 0

Solving
-23 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '23' to each side of the equation.
-23 + 23 + 1b = 0 + 23

Combine like terms: -23 + 23 = 0
0 + 1b = 0 + 23
1b = 0 + 23

Combine like terms: 0 + 23 = 23
1b = 23

Divide each side by '1'.
b = 23

Simplifying
b = 23

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