-9(3b+3)+(28b-2)=0

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Solution for -9(3b+3)+(28b-2)=0 equation:


Simplifying
-9(3b + 3) + (28b + -2) = 0

Reorder the terms:
-9(3 + 3b) + (28b + -2) = 0
(3 * -9 + 3b * -9) + (28b + -2) = 0
(-27 + -27b) + (28b + -2) = 0

Reorder the terms:
-27 + -27b + (-2 + 28b) = 0

Remove parenthesis around (-2 + 28b)
-27 + -27b + -2 + 28b = 0

Reorder the terms:
-27 + -2 + -27b + 28b = 0

Combine like terms: -27 + -2 = -29
-29 + -27b + 28b = 0

Combine like terms: -27b + 28b = 1b
-29 + 1b = 0

Solving
-29 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '29' to each side of the equation.
-29 + 29 + 1b = 0 + 29

Combine like terms: -29 + 29 = 0
0 + 1b = 0 + 29
1b = 0 + 29

Combine like terms: 0 + 29 = 29
1b = 29

Divide each side by '1'.
b = 29

Simplifying
b = 29

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