-9(3b+3)+(28b-5)=0

Solution for -9(3b+3)+(28b-5)=0 equation:

Simplifying
-9(3b + 3) + (28b + -5) = 0

Reorder the terms:
-9(3 + 3b) + (28b + -5) = 0
(3 * -9 + 3b * -9) + (28b + -5) = 0
(-27 + -27b) + (28b + -5) = 0

Reorder the terms:
-27 + -27b + (-5 + 28b) = 0

Remove parenthesis around (-5 + 28b)
-27 + -27b + -5 + 28b = 0

Reorder the terms:
-27 + -5 + -27b + 28b = 0

Combine like terms: -27 + -5 = -32
-32 + -27b + 28b = 0

Combine like terms: -27b + 28b = 1b
-32 + 1b = 0

Solving
-32 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '32' to each side of the equation.
-32 + 32 + 1b = 0 + 32

Combine like terms: -32 + 32 = 0
0 + 1b = 0 + 32
1b = 0 + 32

Combine like terms: 0 + 32 = 32
1b = 32

Divide each side by '1'.
b = 32

Simplifying
b = 32