-9(3b+3)+(28b-7)=0

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Solution for -9(3b+3)+(28b-7)=0 equation:


Simplifying
-9(3b + 3) + (28b + -7) = 0

Reorder the terms:
-9(3 + 3b) + (28b + -7) = 0
(3 * -9 + 3b * -9) + (28b + -7) = 0
(-27 + -27b) + (28b + -7) = 0

Reorder the terms:
-27 + -27b + (-7 + 28b) = 0

Remove parenthesis around (-7 + 28b)
-27 + -27b + -7 + 28b = 0

Reorder the terms:
-27 + -7 + -27b + 28b = 0

Combine like terms: -27 + -7 = -34
-34 + -27b + 28b = 0

Combine like terms: -27b + 28b = 1b
-34 + 1b = 0

Solving
-34 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '34' to each side of the equation.
-34 + 34 + 1b = 0 + 34

Combine like terms: -34 + 34 = 0
0 + 1b = 0 + 34
1b = 0 + 34

Combine like terms: 0 + 34 = 34
1b = 34

Divide each side by '1'.
b = 34

Simplifying
b = 34

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