-9(3b+4)+(28b-2)=0

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Solution for -9(3b+4)+(28b-2)=0 equation:


Simplifying
-9(3b + 4) + (28b + -2) = 0

Reorder the terms:
-9(4 + 3b) + (28b + -2) = 0
(4 * -9 + 3b * -9) + (28b + -2) = 0
(-36 + -27b) + (28b + -2) = 0

Reorder the terms:
-36 + -27b + (-2 + 28b) = 0

Remove parenthesis around (-2 + 28b)
-36 + -27b + -2 + 28b = 0

Reorder the terms:
-36 + -2 + -27b + 28b = 0

Combine like terms: -36 + -2 = -38
-38 + -27b + 28b = 0

Combine like terms: -27b + 28b = 1b
-38 + 1b = 0

Solving
-38 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '38' to each side of the equation.
-38 + 38 + 1b = 0 + 38

Combine like terms: -38 + 38 = 0
0 + 1b = 0 + 38
1b = 0 + 38

Combine like terms: 0 + 38 = 38
1b = 38

Divide each side by '1'.
b = 38

Simplifying
b = 38

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