-9(3b+4)+(28b-3)=0

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Solution for -9(3b+4)+(28b-3)=0 equation:


Simplifying
-9(3b + 4) + (28b + -3) = 0

Reorder the terms:
-9(4 + 3b) + (28b + -3) = 0
(4 * -9 + 3b * -9) + (28b + -3) = 0
(-36 + -27b) + (28b + -3) = 0

Reorder the terms:
-36 + -27b + (-3 + 28b) = 0

Remove parenthesis around (-3 + 28b)
-36 + -27b + -3 + 28b = 0

Reorder the terms:
-36 + -3 + -27b + 28b = 0

Combine like terms: -36 + -3 = -39
-39 + -27b + 28b = 0

Combine like terms: -27b + 28b = 1b
-39 + 1b = 0

Solving
-39 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '39' to each side of the equation.
-39 + 39 + 1b = 0 + 39

Combine like terms: -39 + 39 = 0
0 + 1b = 0 + 39
1b = 0 + 39

Combine like terms: 0 + 39 = 39
1b = 39

Divide each side by '1'.
b = 39

Simplifying
b = 39

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