-9(3b+4)+(28b-4)=0

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Solution for -9(3b+4)+(28b-4)=0 equation:


Simplifying
-9(3b + 4) + (28b + -4) = 0

Reorder the terms:
-9(4 + 3b) + (28b + -4) = 0
(4 * -9 + 3b * -9) + (28b + -4) = 0
(-36 + -27b) + (28b + -4) = 0

Reorder the terms:
-36 + -27b + (-4 + 28b) = 0

Remove parenthesis around (-4 + 28b)
-36 + -27b + -4 + 28b = 0

Reorder the terms:
-36 + -4 + -27b + 28b = 0

Combine like terms: -36 + -4 = -40
-40 + -27b + 28b = 0

Combine like terms: -27b + 28b = 1b
-40 + 1b = 0

Solving
-40 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '40' to each side of the equation.
-40 + 40 + 1b = 0 + 40

Combine like terms: -40 + 40 = 0
0 + 1b = 0 + 40
1b = 0 + 40

Combine like terms: 0 + 40 = 40
1b = 40

Divide each side by '1'.
b = 40

Simplifying
b = 40

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