-9(3z+20)=2(-6z+2)-19

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Solution for -9(3z+20)=2(-6z+2)-19 equation:


-9(3z + 20) = 2(-6z + 2) - 19

We simplify the equation to the form, which is simple to understand
-9(3z+20)=2(-6z+2)-19

Reorder the terms in parentheses
+(-27z-180)=2*(-6z+2)-19

Remove unnecessary parentheses
-27z-180=+2+*(-6z+2+)-19

Reorder the terms in parentheses
-27z-180=+(-12z+4)-19

Remove unnecessary parentheses
-27z-180=-12z+4-19

We move all terms containing z to the left and all other terms to the right.
-27z+12z=+4-19+180

We simplify left and right side of the equation.
-15z=+165

We divide both sides of the equation by -15 to get z.
z=-11

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