-9(4f+1)=-3f-6(-f+8)

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Solution for -9(4f+1)=-3f-6(-f+8) equation: 



-9(4f+1)=-3f-6(-f+8)

We move all terms to the left:

-9(4f+1)-(-3f-6(-f+8))=0

We add all the numbers together, and all the variables

-9(4f+1)-(-3f-6(-1f+8))=0

We multiply parentheses

-36f-(-3f-6(-1f+8))-9=0



We calculate terms in parentheses: -(-3f-6(-1f+8)), so:

-3f-6(-1f+8)

We multiply parentheses

-3f+6f-48

We add all the numbers together, and all the variables

3f-48

Back to the equation:

-(3f-48)



We get rid of parentheses

-36f-3f+48-9=0

We add all the numbers together, and all the variables

-39f+39=0

We move all terms containing f to the left, all other terms to the right

-39f=-39

f=-39/-39

f=1

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