-9(4y-8)=2(y+4)

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Solution for -9(4y-8)=2(y+4) equation: 



-9(4y-8)=2(y+4)

We move all terms to the left:

-9(4y-8)-(2(y+4))=0

We multiply parentheses

-36y-(2(y+4))+72=0



We calculate terms in parentheses: -(2(y+4)), so:

2(y+4)

We multiply parentheses

2y+8

Back to the equation:

-(2y+8)



We get rid of parentheses

-36y-2y-8+72=0

We add all the numbers together, and all the variables

-38y+64=0

We move all terms containing y to the left, all other terms to the right

-38y=-64

y=-64/-38

y=1+13/19

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