-9(6+x)2x=10

Solution for -9(6+x)2x=10 equation:

-9(6+x)2x=10

We move all terms to the left:

-9(6+x)2x-(10)=0

We add all the numbers together, and all the variables

-9(x+6)2x-10=0

We multiply parentheses

-18x^2-108x-10=0

a = -18; b = -108; c = -10;
Δ = b2-4ac
Δ = -1082-4·(-18)·(-10)
Δ = 10944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10944}=\sqrt{576*19}=\sqrt{576}*\sqrt{19}=24\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-24\sqrt{19}}{2*-18}=\frac{108-24\sqrt{19}}{-36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+24\sqrt{19}}{2*-18}=\frac{108+24\sqrt{19}}{-36}
$