-9(b-5)+3(3b+2)=b-(3b-21)

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Solution for -9(b-5)+3(3b+2)=b-(3b-21) equation: 



-9(b-5)+3(3b+2)=b-(3b-21)

We move all terms to the left:

-9(b-5)+3(3b+2)-(b-(3b-21))=0

We multiply parentheses

-9b+9b-(b-(3b-21))+45+6=0



We calculate terms in parentheses: -(b-(3b-21)), so:

b-(3b-21)

We get rid of parentheses

b-3b+21

We add all the numbers together, and all the variables

-2b+21

Back to the equation:

-(-2b+21)



We add all the numbers together, and all the variables

-(-2b+21)+51=0

We get rid of parentheses

2b-21+51=0

We add all the numbers together, and all the variables

2b+30=0

We move all terms containing b to the left, all other terms to the right

2b=-30

b=-30/2

b=-15

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