-9(c+-2)=12+3c

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Solution for -9(c+-2)=12+3c equation: 



-9(c+-2)=12+3c

We move all terms to the left:

-9(c+-2)-(12+3c)=0

We add all the numbers together, and all the variables

-9(c-2)-(3c+12)=0

We multiply parentheses

-9c-(3c+12)+18=0

We get rid of parentheses

-9c-3c-12+18=0

We add all the numbers together, and all the variables

-12c+6=0

We move all terms containing c to the left, all other terms to the right

-12c=-6

c=-6/-12

c=1/2

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