-9(c-2)+3=2(c+7)-8

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Solution for -9(c-2)+3=2(c+7)-8 equation: 



-9(c-2)+3=2(c+7)-8

We move all terms to the left:

-9(c-2)+3-(2(c+7)-8)=0

We multiply parentheses

-9c-(2(c+7)-8)+18+3=0



We calculate terms in parentheses: -(2(c+7)-8), so:

2(c+7)-8

We multiply parentheses

2c+14-8

We add all the numbers together, and all the variables

2c+6

Back to the equation:

-(2c+6)



We add all the numbers together, and all the variables

-9c-(2c+6)+21=0

We get rid of parentheses

-9c-2c-6+21=0

We add all the numbers together, and all the variables

-11c+15=0

We move all terms containing c to the left, all other terms to the right

-11c=-15

c=-15/-11

c=1+4/11

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