-9(d+2)+3(d-8)=6

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Solution for -9(d+2)+3(d-8)=6 equation: 



-9(d+2)+3(d-8)=6

We move all terms to the left:

-9(d+2)+3(d-8)-(6)=0

We multiply parentheses

-9d+3d-18-24-6=0

We add all the numbers together, and all the variables

-6d-48=0

We move all terms containing d to the left, all other terms to the right

-6d=48

d=48/-6

d=-8

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