-9(r+3)+11=-9(11r+)-7

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Solution for -9(r+3)+11=-9(11r+)-7 equation: 



-9(r+3)+11=-9(11r+)-7

We move all terms to the left:

-9(r+3)+11-(-9(11r+)-7)=0

We add all the numbers together, and all the variables

-9(r+3)-(-9(+11r)-7)+11=0

We multiply parentheses

-9r-(-9(+11r)-7)-27+11=0



We calculate terms in parentheses: -(-9(+11r)-7), so:

-9(+11r)-7

We multiply parentheses

-99r-7

Back to the equation:

-(-99r-7)



We add all the numbers together, and all the variables

-9r-(-99r-7)-16=0

We get rid of parentheses

-9r+99r+7-16=0

We add all the numbers together, and all the variables

90r-9=0

We move all terms containing r to the left, all other terms to the right

90r=9

r=9/90

r=1/10

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