-9(r-3)=-7-2(2r+8)

Solution for -9(r-3)=-7-2(2r+8) equation:

-9(r-3)=-7-2(2r+8)

We move all terms to the left:

-9(r-3)-(-7-2(2r+8))=0

We multiply parentheses

-9r-(-7-2(2r+8))+27=0


We calculate terms in parentheses: -(-7-2(2r+8)), so:

-7-2(2r+8)

determiningTheFunctionDomain
-2(2r+8)-7

We multiply parentheses

-4r-16-7

We add all the numbers together, and all the variables

-4r-23

Back to the equation:

-(-4r-23)


We get rid of parentheses

-9r+4r+23+27=0

We add all the numbers together, and all the variables

-5r+50=0

We move all terms containing r to the left, all other terms to the right

-5r=-50

r=-50/-5

r=+10