-9(t-3)-(t+4)=5

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Solution for -9(t-3)-(t+4)=5 equation: 



-9(t-3)-(t+4)=5

We move all terms to the left:

-9(t-3)-(t+4)-(5)=0

We multiply parentheses

-9t-(t+4)+27-5=0

We get rid of parentheses

-9t-t-4+27-5=0

We add all the numbers together, and all the variables

-10t+18=0

We move all terms containing t to the left, all other terms to the right

-10t=-18

t=-18/-10

t=1+4/5

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