-9(t-3)=4(t+2)-t

Solution for -9(t-3)=4(t+2)-t equation:

-9(t-3)=4(t+2)-t

We move all terms to the left:

-9(t-3)-(4(t+2)-t)=0

We multiply parentheses

-9t-(4(t+2)-t)+27=0


We calculate terms in parentheses: -(4(t+2)-t), so:

4(t+2)-t

We add all the numbers together, and all the variables

-1t+4(t+2)

We multiply parentheses

-1t+4t+8

We add all the numbers together, and all the variables

3t+8

Back to the equation:

-(3t+8)


We get rid of parentheses

-9t-3t-8+27=0

We add all the numbers together, and all the variables

-12t+19=0

We move all terms containing t to the left, all other terms to the right

-12t=-19

t=-19/-12

t=1+7/12