-9(v+2)=2v+48

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Solution for -9(v+2)=2v+48 equation: 



-9(v+2)=2v+48

We move all terms to the left:

-9(v+2)-(2v+48)=0

We multiply parentheses

-9v-(2v+48)-18=0

We get rid of parentheses

-9v-2v-48-18=0

We add all the numbers together, and all the variables

-11v-66=0

We move all terms containing v to the left, all other terms to the right

-11v=66

v=66/-11

v=-6

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