-9(v+5)=2v+32

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Solution for -9(v+5)=2v+32 equation: 



-9(v+5)=2v+32

We move all terms to the left:

-9(v+5)-(2v+32)=0

We multiply parentheses

-9v-(2v+32)-45=0

We get rid of parentheses

-9v-2v-32-45=0

We add all the numbers together, and all the variables

-11v-77=0

We move all terms containing v to the left, all other terms to the right

-11v=77

v=77/-11

v=-7

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