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-9(x+1)+5(3x-7)=5(x-5)+13
We move all terms to the left:
-9(x+1)+5(3x-7)-(5(x-5)+13)=0
We multiply parentheses
-9x+15x-(5(x-5)+13)-9-35=0
We calculate terms in parentheses: -(5(x-5)+13), so:We add all the numbers together, and all the variables
5(x-5)+13
We multiply parentheses
5x-25+13
We add all the numbers together, and all the variables
5x-12
Back to the equation:
-(5x-12)
6x-(5x-12)-44=0
We get rid of parentheses
6x-5x+12-44=0
We add all the numbers together, and all the variables
x-32=0
We move all terms containing x to the left, all other terms to the right
x=32
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