-9(x+2)(x+2)=(x-7)(x-7)

Solution for -9(x+2)(x+2)=(x-7)(x-7) equation:

-9(x+2)(x+2)=(x-7)(x-7)

We move all terms to the left:

-9(x+2)(x+2)-((x-7)(x-7))=0

We multiply parentheses ..

-9(+x^2+2x+2x+4)-((x-7)(x-7))=0


We calculate terms in parentheses: -((x-7)(x-7)), so:

(x-7)(x-7)

We multiply parentheses ..

(+x^2-7x-7x+49)

We get rid of parentheses

x^2-7x-7x+49

We add all the numbers together, and all the variables

x^2-14x+49

Back to the equation:

-(x^2-14x+49)


We multiply parentheses

-9x^2-18x-18x-(x^2-14x+49)-36=0

We get rid of parentheses

-9x^2-x^2-18x-18x+14x-49-36=0

We add all the numbers together, and all the variables

-10x^2-22x-85=0

a = -10; b = -22; c = -85;
Δ = b2-4ac
Δ = -222-4·(-10)·(-85)
Δ = -2916
Delta is less than zero, so there is no solution for the equation