-9(x+4)(x-5)=3x(2-3x)

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Solution for -9(x+4)(x-5)=3x(2-3x) equation: 



-9(x+4)(x-5)=3x(2-3x)

We move all terms to the left:

-9(x+4)(x-5)-(3x(2-3x))=0

We add all the numbers together, and all the variables

-9(x+4)(x-5)-(3x(-3x+2))=0

We multiply parentheses ..

-9(+x^2-5x+4x-20)-(3x(-3x+2))=0



We calculate terms in parentheses: -(3x(-3x+2)), so:

3x(-3x+2)

We multiply parentheses

-9x^2+6x

Back to the equation:

-(-9x^2+6x)



We multiply parentheses

-9x^2-(-9x^2+6x)+45x-36x+180=0

We get rid of parentheses

-9x^2+9x^2-6x+45x-36x+180=0

We add all the numbers together, and all the variables

3x+180=0

We move all terms containing x to the left, all other terms to the right

3x=-180

x=-180/3

x=-60

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