-9(x-2)=-2(6+x)+3x

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Solution for -9(x-2)=-2(6+x)+3x equation: 



-9(x-2)=-2(6+x)+3x

We move all terms to the left:

-9(x-2)-(-2(6+x)+3x)=0

We add all the numbers together, and all the variables

-9(x-2)-(-2(x+6)+3x)=0

We multiply parentheses

-9x-(-2(x+6)+3x)+18=0



We calculate terms in parentheses: -(-2(x+6)+3x), so:

-2(x+6)+3x

We add all the numbers together, and all the variables

3x-2(x+6)

We multiply parentheses

3x-2x-12

We add all the numbers together, and all the variables

x-12

Back to the equation:

-(x-12)



We get rid of parentheses

-9x-x+12+18=0

We add all the numbers together, and all the variables

-10x+30=0

We move all terms containing x to the left, all other terms to the right

-10x=-30

x=-30/-10

x=+3

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