-9(x-6)+4x=3/4(12x-8)+5

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Solution for -9(x-6)+4x=3/4(12x-8)+5 equation: 



-9(x-6)+4x=3/4(12x-8)+5

We move all terms to the left:

-9(x-6)+4x-(3/4(12x-8)+5)=0



Domain of the equation: 4(12x-8)+5)!=0

x∈R



We add all the numbers together, and all the variables

4x-9(x-6)-(3/4(12x-8)+5)=0

We multiply parentheses

4x-9x-(3/4(12x-8)+5)+54=0

We multiply all the terms by the denominator


4x*4(12x-8)+5)-9x*4(12x-8)+5)-(3+54*4(12x-8)+5)=0

We add all the numbers together, and all the variables

4x*4(12x-8)+5)-9x*4(12x-8)+5)-(3+54*4(12x=0

Wy multiply elements

16x^2(1+5)-9x*4(12x-8)+54*4(12x+5)-(3=0

We add all the numbers together, and all the variables

16x^26-9x*4(12x-8)+54*4(12x+5)-(3=0

We add all the numbers together, and all the variables

16x^26-9x*4(12x-8)+54*4(12x+5)=0

Wy multiply elements

16x^26-36x^2(1+216x(1=0

We do not support expression: x^26

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