-9(y+2)-8y=-7(y+4)

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Solution for -9(y+2)-8y=-7(y+4) equation: 



-9(y+2)-8y=-7(y+4)

We move all terms to the left:

-9(y+2)-8y-(-7(y+4))=0

We add all the numbers together, and all the variables

-8y-9(y+2)-(-7(y+4))=0

We multiply parentheses

-8y-9y-(-7(y+4))-18=0



We calculate terms in parentheses: -(-7(y+4)), so:

-7(y+4)

We multiply parentheses

-7y-28

Back to the equation:

-(-7y-28)



We add all the numbers together, and all the variables

-17y-(-7y-28)-18=0

We get rid of parentheses

-17y+7y+28-18=0

We add all the numbers together, and all the variables

-10y+10=0

We move all terms containing y to the left, all other terms to the right

-10y=-10

y=-10/-10

y=1

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