-9(y+3)+5(3y-5)=5(y-6)+14

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Solution for -9(y+3)+5(3y-5)=5(y-6)+14 equation: 



-9(y+3)+5(3y-5)=5(y-6)+14

We move all terms to the left:

-9(y+3)+5(3y-5)-(5(y-6)+14)=0

We multiply parentheses

-9y+15y-(5(y-6)+14)-27-25=0



We calculate terms in parentheses: -(5(y-6)+14), so:

5(y-6)+14

We multiply parentheses

5y-30+14

We add all the numbers together, and all the variables

5y-16

Back to the equation:

-(5y-16)



We add all the numbers together, and all the variables

6y-(5y-16)-52=0

We get rid of parentheses

6y-5y+16-52=0

We add all the numbers together, and all the variables

y-36=0

We move all terms containing y to the left, all other terms to the right

y=36

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