-9(y-3)=8y-41

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Solution for -9(y-3)=8y-41 equation: 



-9(y-3)=8y-41

We move all terms to the left:

-9(y-3)-(8y-41)=0

We multiply parentheses

-9y-(8y-41)+27=0

We get rid of parentheses

-9y-8y+41+27=0

We add all the numbers together, and all the variables

-17y+68=0

We move all terms containing y to the left, all other terms to the right

-17y=-68

y=-68/-17

y=+4

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